Question

Simplify 7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

Answer 1

Simplify 7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

Answer 2

`7\sqrt3-4\sqrt6+√(48)-√(54)\\\\=7\sqrt3-4\sqrt6+√(16\cdot3)-√(9\cdot6)\\\\=7\sqrt3-4\sqrt6+√(16)\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}`