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How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O

User Rasso
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1 Answer

5 votes

B(OH)_3=H_3BO_3

then


H_2SO_4+H_3BO_3\longrightarrow~B_2(SO_4)_3+H_2O


\boxed{3H_2SO_4+2H_3BO_3\longrightarrow~B_2(SO_4)_3+6H_2O}
User Saeed Eivazi
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