Question

Triangle STU is located at S (2,1), T (2,3), and U (0,-1). The triangle is then transformed using the rule (x-4, y+3) to form the image S'T'U'. What are the new coordinates of S', T', and U'? Describe what characteristics you would find if the corresponding vertices were connected with the line segments. . Help I don't understand!!

Answer 1

The coordinates of S', T', and U' are (-2,4), (-2,6) and (-4,2) respectively. From the below graph it is clearly noticed that the triangle shifts 4 units left and 3 units up.

Explanation:

The given vertices of triangle STV are S (2,1), T (2,3), and U (0,-1).

The rule of translation is

`(x,y)\rightarrow (x-4,y+3)`

The vertices of triangle S'T'V' are

`S(2,1)\rightarrow (2-4,1+3)=S'(-2,4)`

`T(2,3)\rightarrow (2-4,3+3)=T'(-2,6)`

`V(0,-1)\rightarrow (0-4,-1+3)=V'(-4,2)`

The coordinates of S', T', and U' are (-2,4), (-2,6) and (-4,2) respectively.

From the below graph it is clearly noticed that the triangle shifts 4 units left and 3 units up.

Answer 2

I think the characteristics of the function is drastically change in terms of constructing the vertices and forming the triangle. The new coordinates base on your rules is S(-2.4), T(-2,6) and U(-4,2). I hope you are satisfied with my answer