Question

Which are the solutions of x2 = 19x 1

Answer 1

Here you go.

I was sorta unsure how to read the last part in your question but I tried my best to interpret it

Answer 2

For this case we have the following quadratic equation:

`x ^ 2 = 19x + 1`

Rewriting we have:

`x ^ 2 - 19x - 1 = 0`

Then, using the quadratic formula we have:

`x =(-b+/-√(b^2-4ac))/(2a)`

Substituting values:

`x =(-(-19)+/-√((-19)^2-4(1)(-1)))/(2(1))`

Rewriting:

`x =(19+/-√(361+4))/(2)`

`x =(19+/-√(365))/(2)`

Therefore, the solutions are given by:

`x =(19+√(365))/(2)`

`x =(19-√(365))/(2)`

Answer:

The solutions of the equation are:

`x =(19+√(365))/(2)`

`x =(19-√(365))/(2)`