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the function f(x) = –x2 − 2x 15 is shown on the graph. what are the domain and range of the function? a. the domain is all real numbers. the range is y < 16. b. the domain is all real numbers. the range is y. c. the domain is x. the range is y. d. the domain is x. the range is y ≤ 16.

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-x^2 - 2x + 15 = -(x^2 + 2x - 15) = -(x^2 + 2x + 1 - 15 - 1) = -(x + 1)^2 - (-15 '- 1) = -(x + 1)^2 + 16
Vertex = (-1, 16)
Range = y ≤ 16
The domain is all real numbers. the range is y


User Salgiza
by
8.2k points
4 votes

we have


f(x)=-x^(2) -2x+15

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation


f(x)-15=-x^(2) -2x


f(x)-15=-(x^(2) +2x)

Complete the square. Remember to balance the equation by adding the same constants to each side


f(x)-15-1=-(x^(2) +2x+1)


f(x)-16=-(x^(2) +2x+1)

Rewrite as perfect squares


f(x)-16=-(x+1)^(2)


f(x)=-(x+1)^(2)+16

This is a vertical parabola open downward

The vertex is the point
(-1,16) is a maximun

The domain is the interval--------> (-∞,∞)

All real numbers

The range is the interval-----> (-∞,16]


y\leq 16

All real numbers less than or equal to
16

The graph in the attached figure

therefore

the answer is the option B

the domain is all real numbers. the range is y ≤ 16

the function f(x) = –x2 − 2x 15 is shown on the graph. what are the domain and range-example-1
User Ayyash
by
8.3k points

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