Question

What is the frequency (s-1) of a photon that has an energy of 4.38 × 10-18 J?

Answer 1

6.61 x 10¹⁵ s⁻¹

Procedure

Calculate the frequency of the photon emitted using the formula

`f=(E)/(h)`

Where E is the energy 4.38 × 10-18 J and h is the plank's constant 6.6261 × 10-34 J/s

`f=\frac{4.38\text{ }*10^(-18)\text{ J s}^(-1)}{6.6261*10^(-34)J}=6.610*10^(15)s^(-1)`