Question

Calculate the amount of solution that contains 6.34 grams of NaBr if you have a 4.10% (m/m) solution.

Answer 1

Mass of solute = 6.34 g of NaBr

( m/m ) = 4.10% ( m/m) = 4.10 / 100 => 0.041

T = m / m ( total )

0.041 = 6.34 / m

amount of solution = 6.34 / 0.041

amount of solution = 154.63 g

hope this helps!