Question

what is the resistance of a clock if it has a current of 0.30 a and runs on a 9.0-v battery? 0.033 2.7 9.3 30

Answer 1

R = V/I = 9 / 0.3

R = 30 ohms.

Answer 2

Answer : Resistance of a clock is
`30\ \Omega`.

Explanation :

It is given that :

The current flowing in the clock, I = 0.3 A

Potential difference, V = 9 V

According to Ohm's law :

`V=I* R`

So,

`R=(V)/(I)`

`R=(9\ V)/(0.3\ A)`

`R=30\ \Omega`

`\Omega` is the SI unit of the resistance given by a physicist Georg Simon Ohm.

So, the correct option is (d) i.e.
`30\ \Omega`

Hence, this is the required solution.