9.8k views
2 votes
How many moles of MgS2O3 are in 167 g of the compound?

1 Answer

4 votes
Molar mass MgS₂O₃ = 24 + 32 x 2 + 16 x 3 = 136 g/mol

1 mole ---------------- 136 g
? mole --------------- 167 g

moles = 167 x 1 / 136

moles = 167 / 136

= 1.227 moles of MgS₂O₃

hope this helps!
User BBlackwo
by
8.6k points

Related questions

asked Feb 15, 2017 151k views
Norrius asked Feb 15, 2017
by Norrius
8.2k points
1 answer
2 votes
151k views
asked Aug 20, 2017 9.9k views
Shane Davis asked Aug 20, 2017
by Shane Davis
8.0k points
1 answer
4 votes
9.9k views
asked Mar 16, 2017 161k views
Kulgar asked Mar 16, 2017
by Kulgar
8.1k points
1 answer
4 votes
161k views