Question

7. a light bulb connected to a 9-v battery has a current of 1.5 a flowing. a. find the resistance of the light bulb (in ohms) b. find the power drawn by the light bulb (in w)

Answer 1

a) Resistance, R = Voltage, V / Current, I

= 9 V / 1.5 A

= 6 Ω, 6 Ohms

b) Power P = IV

= 1.5*9 = 13.5 W

= 13.5 Watts

Answer 2

`R=(V)/(I)`

`R=(9)/(1.5)=6\ ohms`


`P=((V^(2)))/(R)`

`P=((9^(2)))/(6)=13.5\ watts`