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What is the magnetic field if a force of 1.38N is experienced by a 6.12C charge traveling at 7.82m/s?34.7T0.0288T0.567T1.76T
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What is the magnetic field if a force of 1.38N is experienced by a 6.12C charge traveling at 7.82m/s?34.7T0.0288T0.567T1.76T

User Marco Wahl
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1 Answer

13 votes
13 votes

We can find the magnetic field as follows:


\begin{gathered} B=(F)/(qv) \\ where: \\ q=6.12C \\ v=7.82m/s \\ F=1.38N \\ Therefore: \\ B=(1.38)/(6.12\cdot7.82)=(1.38)/(47.8584) \\ B=0.0288T \end{gathered}

Answer:

0.0288 T

User Jerry Okafor
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