we are given with a circle with the center at (3,3) and one that passes through (6,5). The equation of a circle is (x-h)^2 + (y-k)^2 = r^2. In this case h = 3 and k = 3. Substituting, h and k and x = 6 and y = 5, r^2 is obtained to be 13. Among these points, A. point (1,6) fits to the equation.