Question

calculate the amount of energy (in kJ) to convert 337 grams of liquid water from 0 degrees celsius to water vapor at 177 degrees celsius.

Answer 1

Do you have any options

Answer 2

The mount of heat required is 249.690 kJ.

Step-by-step explanation:

Mass of the water,m =337 g

Specific heat capacity of the water,c = 4.186 J/g °C

Change in temperature =
`\Delta T=177^oC-0^oC=177^oC`

Q = Heat required

`Q=mc\Delta T=337 g* 4.186 J/g ^oC* 177^oC=249,690.7 J=249.690 kJ`

1 kilo Joule = 1000 joules

The mount of heat required is 249.690 kJ.