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The equation of a line that passes through point (7,3) and is parallel to y=2\7x-3

User Ashu Kumar
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1 Answer

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The general form of the equation is:
y = mx + b
We know that the slope m of the required line is 2/7, the reason being that the two lines must be parallel and therefore must have the same slope.
We can now write an interim equation:

y=(2)/(7)x+b
When the values of the given point, x=7 and y=3, are plugged into the interim equation we get:
3 = 2 + b
Therefore b = 1, and the required equation is:

y=(2)/(7)x+1
User Jornh
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