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the pressure of gas in a cylinder is 70 kilopascals. if the volume of the cylinder is reduced from 8.0 liters to 4.0 liters, what should be the pressure of the gas in the cylinder?

User Pacerier
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By Boyle's law:

P₁V₁ = P₂V₂

70*8 = P₂*4

P₂*4 = 70*8

P₂ = 70*8/4 = 140

P₂ = 140 kiloPascals.
User Andre Bossard
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