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How long is the arc intersected by a central angle of 5pi/3 radians in a circle with a radius of 2 ft? Round your answer to the nearest tenth. Use 3.14 for pi

A. 2.6 ft
B. 7.0 ft
C. 10.5 ft
D. 31.4 ft

2 Answers

1 vote
Length of an arc of a circle:
L = n / 2π ·2 ·r · π
L = (5π/3 ·2 ·2 ·3.14 ) : 2π = 5/3 · 6.28 = 10.47 ≈ 10.5
Answer: C) 10.5 ft.
User Stephen Klancher
by
8.2k points
5 votes

Answer:

C


Explanation:

The arc length formula (in radians) is:


s=r\theta

Where,


  • s is the arc length

  • r is the radius of the circle

  • \theta is the angle intercepted by the arc [in radians]

It is given that radius,
r=2 and angle,
\theta=(5\pi)/(3)


Substituting these values in the arc length formula gives us:


s=(2)((5\pi)/(3))\\s=(10\pi)/(3)

Using
\pi as
3.14 and rounding to nearest tenth gives us:


s=((10)(\pi))/(3)\\s=10.5 ft

Correct answer is C.

User CPB
by
7.7k points
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