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How much heat is needed to rise the temperature of 72g of water by 80^c?

1 Answer

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Mass of water = 72 g = 72 /1000 = 0.072 kg
Temperature rise = 80°C

Heat gained = mcθ

Where m = mass in kg, c is specific heat capacity of water = 4200 J/kg°C
θ = Temperature rise.

Heat gained = mcθ

= 0.072 * 4200 * 80 = 24192

So heat needed = 24 192J.
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