Question

In TUV, the measure of V=90°, the measure of T=24°, and TU = 7.1 feet. Find the length of UV to the nearest tenth of a foot.

Answer 1

let the length UV be y feet

The triangle is a right angled triangle, with opposite= y, hypothenus = 7.1 feet

`\begin{gathered} \text{ using sin}\theta\text{ = }\frac{\text{opposite}}{\text{adjacent}} \\ \sin \text{ 24 = }(y)/(7.1) \\ y=\text{ 7.1 x sin 24} \\ y=\text{ 7.1 x 0.4067} \\ y=\text{ 2.887} \\ y\text{ = 2.9 feet (nearest tenth)} \end{gathered}`

Hence, length UV = 2.9 feet ( nearest tenth)