Question

Can you help me i just need to fill in the blanks

Answer 1

a * b = -40 (a)

a + b = -6 (b)

Solve (b) for (a)

a = -6-b

Replace on (a) and solve for b

-6-b * b = -40

-6b -b^2 = -40

-b^2-6b+40 = 0

apply quadratic equation:

`\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot C}}{2\cdot A}=\frac{6\pm\sqrt[]{36-4\cdot-1\cdot40}}{2\cdot-1}=(6\pm26)/(-2)`

positive : 6+26/-2 = 32/-2 = -16

negative = 6-26/-2 = 10

Use the negative:

10 * b = -40

b = -40 /-10

b= 4