139,484 views
0 votes
0 votes
A recent report indicated that 16 2/3% of all residents of a state did not have health insurance. What fraction of residents were uninsured?

User Hardwired
by
2.5k points

1 Answer

23 votes
23 votes

The fraction of the residents were insecured were,


\begin{gathered} (16(2)/(3))/(100)=((50)/(3))/(100) \\ =(50)/(300) \\ =(1)/(6) \end{gathered}

Thus, the required fraction is 1/6.

User Guy Daher
by
3.3k points