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How do you solve

sin9x/1-cos^2(9x)

1 Answer

4 votes
using formula sin^2 x +cos^2 x = 1 you get 1 - cos^2(9x) = sin^2(9x)

so in this way this fraction will be rewrited

sin9x/(1-cos^2(9x) = sin9x / sin^2(9x) = 1/sin9x
User Gianluca
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