Question

Given the following balanced reaction between nitrogen gas and oxygen gas to produce nitrous oxide gas, how many moles of nitrous oxide gas are produced from 1.65 moles of nitrogen gas?

Answer 1

There are produced 1,65 mol of nitrous oxide gas.

Step-by-step explanation:

The reaction of nitrogen gas and oxygen gas to produce nitrous oxide gas is:

2 N₂(g) + O₂(g) → 2 N₂O(g)

This balanced reaction is saying that per 2 moles of nitrogen gas in excess of oxygen there are produced 2 moles of nitrous oxide gas. That means that per 1,65 moles of nitrogen gas there are produced:

1,65 mol N₂(g) ×
`(2 mol N_(2)O)/(2 mol N_(2))` = 1,65 mol N₂O

I hope it helps!

Answer 2

The balance chemical equation is
2N2 + O2 ---> 2N2O.

We can solve how many moles of nitrous oxide gas from 1.65 moles of nitrogen gas. The balance equation is a critical information to answer this problem since it gives the ratio of nitrous oxide gas produced to the nitrogen used. 2 moles of nitrous oxide gas is produced from 2 moles of nitrogen gas is used. Hence there is 1.65 moles of nitrous oxide gas produced.