Question

the population of a town is 7,000 and it grows at a rate of 4.6 percent. what will the population be in 10 years.

Answer 1

Data Input

P = 7000

r = 4.6%

t = 10 years

Procedure

The population after 10 years can be found by

`\begin{gathered} P=P_o(1+(t)/(100))^t \\ \end{gathered}`

where

P is the population after 10 years

t is the times

r is the rate of interest

Po is the initial population

`\begin{gathered} P(t)=7000(1+(4.6)/(100))^(10) \\ P(t)=7000(1+0.046)^(10) \\ P(t)=7000(1.046)^(10) \\ P(t)=10975 \end{gathered}`

The population would be 10975