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What is an equation of the line that passes through the point (-2, -3) and is perpendicular to the line x + 3y=24

User Shershen
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1 Answer

10 votes
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Given data:

The given point is (-2, -3).

the given equation x+3y=24.

The standard equation of the line is,

y=mx+c.

Compare the given equation with the above equation.

y=-x/3+8

The slope of the line perpendicuar,

(-1/3)(m)=-1

m=3

The given of the line which is perpendicuar to the given line is,

y-(-3)=3(x-(-2))

y+3=3x+6

y=3x+3

Thus, the equation of line is y=3x+3.

User Mike Andrews
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