Question

If T is the point at the given distance on the unit circle C from P (1, 0), determine the quadrant in which T lies:

11pi/6

a) I
b) II
c) III
d) IV

Answer 1

Hello,

Answer D

9π/6<11π/6<12π/6
Quadrant IV

Answer 2

Answer:

Option d) is correct

Explanation:

T is a point at a given distance on the unit circle from P(0,1) .

Clearly, the point P(0,1) lies on the circle itself .

To find: the quadrant in which T lies

Given: angle at which point T lies is
`(11\pi)/(6)`.

Solution :

`(11\pi)/(6)=(11* 180^(\circ))/(6)=11* 30^(\circ)=330^(\circ)`

As
`270^(\circ)< 330^(\circ)< 360^(\circ)`,

So, basically we are talking about the fourth quadrant as angle
`330^(\circ)` lies in the fourth quadrant .

Therefore, point T lies in quadrant IV.

i.e If T is the point at the given distance on the unit circle C from P (1, 0), then T lies in the IV quadrant.

So, option d) is correct .