Question

18a4w + 168a²bk – 72a4k - 42a_bw

Answer 1

We have the following expression:

`18a^4w+168a^2bk-72a^4k-42a^2bw`

Lets find the greatest common factor of all terms. We can note that the gcf of the number is

`\begin{gathered} \text{the factors of 18 are: }1,2,3,6,9,18 \\ Thefactorsof42are\colon1,2,3,6,7,14,21,42 \\ Thefactorsof72are\colon1,2,3,4,6,8,9,12,18,24,36,72 \\ Thefactorsof168are\colon1,2,3,4,6,7,8,12,14,21,24,28,42,56,84,168 \end{gathered}`

They have in common the number 6, then we can rewritte our expression as:

`6(3a^4w+28a^2bk-12a^4k-7a^2bw)`

Regarding the variables, we can note that the term

`a^2`

is in all the terms of our expression, then we have

`6a^2(3a^2w+28bk-12a^2k-7^{}bw)`