Step-by-step explanation:
Sodium and oxygen react to produce sodium oxide. The balanced equation of the reaction is:
4 Na + O₂ ----> 2 Na₂O
First we can convert the 45.35 g of Na₂O into moles using its molar mass.
molar mass of Na = 22.99 g/mol
molar mass of O = 16.00 g/mol
molar mass of Na₂O = 2 * 22.99 g/mol + 1 * 16.00 g/mol
molar mass of Na₂O = 61.98 g/mol
moles of Na₂O = 45.35 g * 1 mol/(61.98 g)
moles of Na₂O = 0.7317 moles
4 Na + O₂ ----> 2 Na₂O
According to the coefficients of the reaction, 4 moles of Na will react with 1 mol of O₂ to produce 2 moles of Na₂O. Then the molar ratio between O₂ and Na₂O is 1 to 2. We can use that relationship to find the answer to our problem.
1 mol of O₂ : 2 moles of Na₂O
moles of O₂ = 0.7317 moles of Na₂O * 1 mol of O₂/(2 moles of Na₂O)
moles of O₂ = 0.3659 mol
Answer: 0.3659 moles of oxygen are needed to produce 45.35 g of sodium oxide.