Question

The specific gravity of iron is 7.87, and the density of water at 4.00 ∘C is 1.00 g/cm3. You can use this information to find the density of iron. Find the volume occupied by 4.50 g of iron.

Answer 1

Answer: The volume of iron occupied is
`0.572cm^3`

Step-by-step explanation:

The relationship between specific gravity and density of a substance is given as:

`\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}`

Specific gravity of iron = 7.87

Density of water =
`1.00g/cm^3`

Putting values in above equation we get:

`7.87=\frac{\text{Density of iron}}{1.00g/cm^3}\\\\\text{Density of iron}=7.87g/cm^3`

To calculate volume of a substance, we use the equation:

`\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}`

Density of iron =
`7.87g/cm^3`

Mass of iron = 4.50 g

Putting values in above equation, we get:

`7.87g/cm^3=\frac{4.50g}{\text{Volume of iron}}\\\\\text{Volume of iron}=0.572cm^3`

Hence, the volume of iron occupied is
`0.572cm^3`

Answer 2

Specific gravity is defined as the ratio of the density of a substance to the density of reference substance. In this case the reference substance is water. Given that the density of water at 4.00 C is 1.00 g/cm3, then density of iron is 7.87 g/cm3.

Given 4.50 g iron (cm3 iron/ 7.87 g iron) = 0.571 cm3