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Sanyam Goel · Answer 1 · 2023-10-22T04:36:21+0000

A table is given with the number of gallons used in one row and the corresponding distance travelled in the second row. The relation between the gallons of gas used and the distance are given to be proportional.

The relation between the distance d and the number of gallons used g can be expressed as,

$d=kg\text{ -----(1)}$

Here, k is the constant of proportionality.

Make a plan.

The constant of proportionality can be found by putting the value of g from the table and the corresponding distance d in the equation d=kg and solving the equation for k.

Put g=3 and d=99 in equation (1) to find k.

$\begin{gathered} 99=k*3 \\ (99)/(3)=k \\ 33=k \end{gathered}$

Put g=5 and d=165 in equation (1) and solve for k.

$\begin{gathered} 165=k*5 \\ (165)/(5)=k \\ 33=k \end{gathered}$

So, the constant of proportionality is k=33

Now, in the fourth column, distance d=264. To find the corresponding value for gas g , put k=33 and d =264 in equation (1) and solve for g .

$\begin{gathered} 264=g*33 \\ (264)/(33)=g \\ 8=g \end{gathered}$

So, when d=264, g=8.

Now, in the fifth column, distance d=330. To find the corresponding value for gas g , put k=33 and d =330 in equation (1) and solve for g .

$\begin{gathered} 330=33g \\ (330)/(33)=g \\ 10=g \end{gathered}$

So, when d=330, g=10

Now, in eighth column , gas, g=15. To find the corresponding value for distance d , put k=33 and g=15 in equation (1) and solve for d .

$\begin{gathered} d=33*15 \\ d=495 \end{gathered}$

So, when g=15, d=495.

So, the unfilled spaces in the table can be filled as:

.

Date: LESS Name: Math in the MPG Real World Meagan wants to know how many miles per-example-1

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