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If 7.84 x 10^7 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3 x 10^8 m/s.

7.06 x 10^24

8.71 x 10^-4

8.71 x 10^-7

8.71 x 10^-10

User Revgum
by
6.7k points

2 Answers

3 votes

Answer : The mass lost would be,
8.71* 10^(-10)Kg

Solution : Given,

Energy released =
7.84* 10^(7)J=7.84* 10^(7)\text{ Kg }m^2/s^2


(1J=1\text{ Kg }m^2/s^2)

Speed of light 'c' =
3* 10^(8)m/s

Formula used :


E=m* c^2

where,

E = energy

m = mass

c = speed of light

Now put all the given values in the above formula, we get


7.84* 10^(7)\text{ Kg }m^2/s^2=m* (3* 10^(8)m/s)^2


m=8.71* 10^(-10)Kg

Therefore, the mass lost would be,
8.71* 10^(-10)Kg

User Lucasweb
by
7.6k points
3 votes
Use the formula
E=mc^2

plug the values,

The amount of mass in kilograms would be lost is 8.71 x 10^-10
User Orka
by
7.9k points