Question

A truck has an initial velocity of 3.0 m/s and after 3.5 seconds, its velocity is 12.0 m/s. Calculate the magnitude of its acceleration.Express your answer with 1 decimal place (round accordingly)

Answer 1

`\begin{equation*} 2.6\text{ }m\/s^2 \end{equation*}`

Step-by-step explanation

Parameters given:

Initial velocity, u = 3.0 m/s

Final velocity, v = 12.0 m/s

Time elapsed, t = 3.5 s

To find the magnitude of the acceleration of the truck, apply the formula for acceleration:

`a=(v-u)/(t)`

Therefore, the acceleration of the truck is:

`\begin{gathered} a=(12.0-3.0)/(3.5)=(9)/(3.5) \\ \\ a=2.6\text{ }m\/s^2 \end{gathered}`

That is the acceleration to 1 decimal place.