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One of two complementary angles is 4 degrees more than the other. Find the angles. (Recall that complementary angles are angles whose sum is 90 degrees.)

Which of the following equations can not be used to solve the problem if x represents one of the angles?

User Cubius
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\displaystyle \\ \alpha + \beta = 90^o \\ \alpha - \beta = 4^o \\ \texttt{----------- } + \\ 2\alpha ~~/~= 94^o \\ \\ \alpha = (94)/(2) = \boxed{47^o}\\ \\ \beta = 90 -\alpha = 90 - 47 = \boxed{43^o}



User France
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