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I need help with this practice Having trouble with it

I need help with this practice Having trouble with it-example-1
User Prince Hernandez
by
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1 Answer

18 votes
18 votes

Answer: We have to solve the sinusoidal equation on the Interval [0,2pi):


-8\cos (x)=3

Simplifying gives:


\cos (x)=-(3)/(8)\Rightarrow(1)

Taking the functional Inverse gives:


x=\cos ^(-1)(-(3)/(8))

The answer is:


x\approx1.955r\Rightarrow\lbrack0,2\pi)

User MicSokoli
by
2.6k points
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