Solve by factorization 48n^2 -3n^4=0

Caesar Ralf asked May 26, 2023

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5 votes

Caesar Ralf asked May 26, 2023

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14 votes

Given:-

To find the value by factorization.

So now we simplify,

$\begin{gathered} 48n^2-3n^4=0 \\ 3n^2(16-n^2)=0 \\ 3n^2=0,16-n^2=0 \\ n=0,n^2=16 \\ n=0,n=14 \end{gathered}$

So the values are 0 and 14.

Igraczech answered Jun 2, 2023

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