3x+2y= 12 (a)
y= x+1 (b)
Replace the value of y (b) on the first equation (a), and solve for x
3x+2(x+1) = 12
Apply distributive property:
3x+2(x)+2(1) = 12
3x+2x+2 =12
Combine like terms
5x+2=12
Subtract 2 from both sides of the equation:
5x+2-2 = 12-2
5x= 10
Divide both sides by 5:
5x/5 = 10/5
x = 2
Plug x in (b) and solve for y
y= x+1
y= 2+1
y=3
Solution: (2,3) option A