15,003 views
39 votes
39 votes
Please need help there are two parts of this problem

Please need help there are two parts of this problem-example-1
User Simoraman
by
2.8k points

1 Answer

14 votes
14 votes

Answer:

The mean is 87.43.

The standard derivation is 28.11.

Step-by-step explanation:

If we multiply each number by three, we have:

19*3 = 57

23*3 = 69

25*3 = 75

27*3 = 81

30*3 = 90

32*3 = 96

48*3 = 144

First, let's calculate the mean:

The means (x) is found by adding up the values and then dividing by the number of values that you added.

x = (57+69+75+81+90+96+144)/7

x = 87.42

The mean is 87.43.

Now, let's calculate the standard derivation of the sample:

The standard derivation (s) can be estimated as follows:


s=\sqrt[]{(\sum ^n_(i\mathop=1)(x_i-x)^2)/(n-1)}

Where n is the number of the samples, xi are the values of the samples (57, 69, ...) and x is the mean.

In this exercise, we have:


\begin{gathered} s=\sqrt[\square]{((57-87.43)^2+(69-87.43)^2+(75-87.43)^2+(81-87.43)^2+(90-87.43)^2+(96-87.43)^2+(144-87.43)^2)/(7-1)} \\ s=\sqrt[]{790.29} \\ s=28.11 \end{gathered}

The standard derivation is 28.11.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.