Question

Renting a carWhen renting a car two options listed below are given. You need the car for 3 days. How many miles must you travel in order for option 2 to be the better option? Tell me your variable and what it represents. Then use that variable to set up an equation you can solve to get the answer.Option 1Daily fee $50Cost per mile $0.15Option 2Daily fee $65Unlimited miles

Answer 1

We have two options (OP) when renting a car:

Cost of OP1 (COP1):

COP1 = Dayly fee = $50, Cost per mile = $0.15

Since you need the car for three days, the cost for renting the OP1 will be:

OP1 = 50*3 + 0.15x

COP1 = 150 + 0.15x

where x is the miles

Cost of OP2 (COP2):

COP2 = Dayly fee = $65, Cost per mile = $0.00

For three days, the cost for OP2 will be:

COP2 = 65*3

COP1 = $195

Now we will calculate in which situation OP2 is better (cheaper) than OP1.

That is, COP2

195<150+0.15x

195-150<0.15x

45<0.15x

45/0.15300or

x>300 miles

You have to travel more than 300 miles to option 2 be the best option.