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How would one prepare 50.0mL of a 3.00M solution of NaOH using 7.10M stock solution?Please help solve and explain

User UserJA
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1 Answer

15 votes
15 votes

Answer

V2 = 21.13 mL

Step-by-step explanation

Given:

Initial volume (V1) = 50.0 mL

Initial concentration (C1) = 3.00 M

Final concentration (C2) = 7.10 M

Required: The volume to be added to make 7.10 M concentration

Solution:

To solve this problem, we use the following formula

C1V1 = C2V2 where C1 and C2 are initial and final concentration, V1 and V2 are initial and final volume.

So we want V2, lets re-arrange the equation.

V2 = C1V1/C2

V2 = (3.00 M x 50.0 mL)/7.10 M

V2 = 21.13 mL

User Diego Cheng
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