For an equation of the form y = a(x - h)² + k the coordinates of the vertex are (h, k). For the first function g(x) = -4(x - 3)² + 5 we can notice that the coordinates of the vertex are (3, 5), similarly, for the thidr function f(x) = -5(x + 3)² - 4, the vertex is (-3, -4).
In order to determine the x-intercept of a function, we can factor it and determine what values of x make the value of the function 0.
For the second function p(x) = 4(x + 3)(x - 5), we can notice that when x is -3 or 5 p(x) = 0, in the given optios we only have x-intercept of 5, then that would be the key aspect of the graph of p(x).
Similarly, for the function h(x) = 3(x - 4)(x + 5) when x = 4 or x = -5 h(x) = 0, then the key aspect of the graph of this function is a x-intercept of 4.
For q(x) = 5(x + 4)(x - 3), q(x) = 0 at x = 3 and x = -4. Then the key aspect of the graph of this function is a x-intercpet of 3.