Question

h(r) = -(r +9)^2 + 361) What are the zeros of the function?Write the smaller r first, and the larger r second.smaller r =larger r =2) What is the vertex of the parabola?

Answer 1

The given function is

`h(r)=-(r+9)^2+36`

To find the zeros, we make h(r) = 0.

`\begin{gathered} -(r+9)^2+36=0 \\ -(r+9)^2=-36 \\ (r+9)^2=36 \\ \sqrt[]{(r+9)^2}=\sqrt[]{36} \\ r+9=\pm36 \\ r_1=36-9=27 \\ r_2=-36-9=-45 \end{gathered}`

(1) The smaller root is -45. The larger root is 27.

(2) The vertex of the parabola is (-9, 36), given by the function form.