Question

It says to solve I don't remember much about doing logs

Answer 1

remember

`log_(b)m^(n)=nlog_(b)m`


`1/4log_(5)81=log_(5)81^(1/4)=log_(5)3`

`1/2log_(5)64=log_(5)64^(1/2)=log_(5)8`

we now have

`log_(5)n=log_(5)3+log_(5)8`
remember

`log_(b)m+log_(b)n= log_(b)(mn)` so

`log_(5)3+log_(5)8= log_(5)(3*8)=log_(5)24`

`log_(5)n=log_(5)24`
therefor n=24