Question

Factor:

x2 + 49
A.(x + 7i)(x - 7i)
B.(7x + i)(7x - i)
C.(x + 7i)(x + 7i)
D.(x - 7l)(x - 7i)

Answer 1

`\begin{gathered} (x+7i)\cdot(x-7i) \\ x=7i,-7i \end{gathered}`

Explanation:

We have the following expression

`f(x)=x^2+49`

we factor and we have:

`\begin{gathered} x^2+49=0 \\ x^2=-49 \\ x=\sqrt[]{-49} \\ x=\pm7i \\ x=7i,-7i \end{gathered}`