Question

What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?

(–6, 0), (2,0)
(–2, –16), (0, –12)
(–6, 0), (–2, –16), (2, 0)
(0, –12), (–6, 0), (2, 0)

Answer 1

Coordinates are (–6, 0), (2,0).

Explanation:

Given the function
`f(x) = x2+4x-12`

we have to find the x-intercepts of the graph of the function f(x).

`y = x2+4x-12`

As the value of y coordinate is 0 on x-axis which gives the x-intercepts of the function.

Put y=0 in above function we get the x-intercepts.

`x^2+4x-12=0`

⇒
`x^2+6x-2x-12=0`

⇒
`x(x+6)-2(x+6)=0`

⇒
`(x-2)(x+6)=0`

⇒ x=2 and x=-6

Hence, x-intercepts are 2 and -6

⇒ Coordinates (–6, 0), (2,0).

Option 1 is correct.