Question

Solve by square root
`(3x - 2) ^(2) = - 12`

Answer 1

Solve by square root;

`(3x-2)^2=-12`

We start by taking the square root of both sides, and we'll have;

`\sqrt[]{(3x-2)^2}=\pm\sqrt[]{-12}`

Note that the square root sign cancels out the square sign on the left side.

`3x-2=\pm\sqrt[]{-12}`

The square root of negative 12 can be splitup into the following;