Question

Which equation has an a-value of 1, a b-value of –3, and a c-value of –5?

0 = –3x – 5 + x2
0 = x – 3 – 5x2
0 = 3x – 5 – x2
0 = –3x + 5 – x2

Answer 1

a

Explanation:

Answer 2

Option (a) is correct.

For given values a = 1 , b = -3 , c = -5 the quadratic equation is
`0=-3x-5 + x^2`

Explanation:

Given : a = 1 , b = -3 , c = -5

We have to write the quadratic equation having a = 1 , b = -3 , c = -5 and choose the correct option.

The standard form of quadratic equation is
`ax^2+bx+c=0` , where a, b, c are constant integers.

Given : a = 1 , b = -3 , c = -5

Then Substitute, we get,

`x^2-3x-5=0`

Thus, the obtained quadratic equation is same as option (a)
`0=-3x-5 + x^2`

Thus, For given values a = 1 , b = -3 , c = -5 the quadratic equation is
`0=-3x-5 + x^2`