Question

Wyatt room is a rectangular with a perimeter of 40 feet. the width of room is 8 feet .what is the length of the room

Answer 1

perimiter=2(legnth+width)
perimiter=40
width=8
40=2(legnth+8)
divide both sides by 2
20=legnth+8
minus 8 both sides
12=legnth

legnth=12 feet

Answer 2

width= 8ft
lenght=x
Perimeter of a rectangle=2 length + 2 width


Therefore:
2x+2(8 ft)=40 ft
2x+16 ft=40 ft
2x=40 ft-16ft
2x=24 ft
x=24 ft/2
x=12 ft

Answer: the lenght of the room will be 12 ft.