Question

Can somebody help me with #21 ? I really don’t understand how to solve this

Answer 1

(a) 80 ft/sec

(b) 0.0125 sec/ft. This tells us that the pace of the car skid was 0.0125 sec/ft.

Step-by-step explanation

Given function:

Where v is the velocity, g is the acceleration due to gravity (32 ft/sec²), d is the length, and f is the friction coefficient of the surface.

(a) The how fast, v(d) the car travel was traveling when it lost control can be calculated by putting g = 32 ft/sec², f = 0.5 and d = 200 ft into the given function:

`\begin{gathered} v(d)=√(2*32*0.5*200) \\ \\ v(d)=√(6400) \\ \\ v(d)=80\text{ }ft\text{/}sec \end{gathered}`

(b) The inverse of the function v(d) is:

`(1)/(v(d))`

From part a, v(d) = 80 ft/sec, therefore, the inverse is:

`(1)/(v(d))=\frac{1}{80\text{ }ft\text{/}sec}=0.0125\text{ }sec\text{/}ft`

This tells us that the pace of the car skid was 0.0125 sec/ft.