Write the equation of the line perpendicular to y=-5/7x+1 through the point (5,10). The answer should be in slope-intercept form
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Slope-intercept form
y= mx + b
b = y-intercept
m is the slope
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y=-5/7x+1
m= -5/7
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The perpendicular line has the m2 slope
m1* m2= -1
m2= -1/ m1
m1 = -5/7
m2= 7/5 = 1 2/5
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Using the point-slope form
y- y1 = m (x- x1)
and the point (5,10)
x1= 5; y1= 10
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Remplacing the information
y- 10 = 7/5 (x- 5)
y = 7/5 x - 5*7/5 + 10
y = 7/5 x - 7+ 10
y = 7/5 x + 3
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Answer
The line perpendicular to y=-5/7x+1 through the point (5,10) in slope-intercept form is y = 7/5 x + 3