Question

4 C3H6(g) + 6 NO(g) → 4 C3H3N(g) + 6 H2O(g) + N2(g) How many grams of C3H3N can be obtained from 651 kg of C3H6

Answer 1

820866.45 grams C₃H₃N can be obta

Step-by-step explanation

Given balanced equation:

`4C_3H_6\mleft(g\mright)+6NO\mleft(g\mright)\to4C_3H_3N\mleft(g\mright)+6H_2O\mleft(g\mright)+N_2\mleft(g\mright)`

Given reacting mass of C₃H₆ = 651 kg

What to find:

The mass of C₃H₃N obtained from 651 kg of C₃H₆

Step-by-step soltion:

From the Periodic Table:

Molar mass of C₃H₆ = 42.08 g/mol

Molar mass of C₃H₃N = 53.06 g/mol

You need to convert the given reacting mass of C₃H₆ from kilograms, (kg) to grams, (g).

Conversion factor:

1 kg = 1000 g

So 651 kg = 651 x 1000 = 651,000 grams

From the balanced equation above;

(4 mol x 42.08 g/mol) = 168.32 g C₃H₆ produced (4 mol x 53.06 g/mol) = 212.24 g C₃H₃N

Therefore 651,000 g C₃H₆ will produce

`\frac{651000\text{ g }C_3H_6*212.24\text{ }C_3H_3N}{168.32\text{ g }C_3H_6}=820866.45\text{ grams }C_3H_3N`