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The square of a number exceeds that number by 12. What are the two possible solutions?

3 or -4
3 or 4
-3 or 4

2 Answers

5 votes
The square of a number exceeds that number by 12. What are the two possible solutions would e B i think

User Keith Fitzgerald
by
8.9k points
4 votes
x^2=x+12
minus x+12 both sides
x^2-x-12=0
factor
(x-3)(x+4)=0
set each to zero

x-3=0
x=3

x+4=0
x=-4

x=3 or -4

answer is first one
User Axel Rauschmayer
by
7.1k points

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